If ∆ABC <span lan

We know that, sides of one triangle are proportional to the side of the other triangle, and then their corresponding angles are also equal, so by SSS similarity, triangles are similar.

∆ABC ∼ ∆EDF

AB/ED = BC/DF = AC/EF

(By similarity property)

Taking first two terms, we get

AB/ED = BC/DF

⇒ AB.DF = ED.BC

So, option (d) is true

Taking last two terms, we get

BC/DF = AC/EF

⇒ BC.EF = AC.DF

So, option (A) is true

Taking first and last terms, we get,

AB/ED = AC/EF

⇒ AB.EF = ED.AC

Hence, option (b) is true.