Q. 34.5( 11 Votes )

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Answer :

Since |AB|= |A||B|



= 2(17×12 – 5×20) – 3(13×12 – 5×15) + 7(13×20 – 15×17)


= 2(204 – 100) – 3(156 – 75) + 7(260 – 255)


= 2×104 – 3×81 + 7×5


= 208 – 243 +35


= 0


Now |A|2 = |A|×|A|


|A|2= 0


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