Q. 24.7( 3 Votes )

For ΔPQR and ΔXYZ, the correspondence PQR YZX is a similarity. mP = 2mQ and mX = 120. Find mY.

Answer :

Given, ΔPQR and ΔXYZ

P = 2Q and X = 120

If the correspondence PQRYZX is a similarity then

mP = mX ... (i)

mQ = mY ... (ii)

mR = mZ ... (iii)

From eq. (i) and (ii)

P = 120

Because mP = 2mQ

Hence, 2Q = 120

Q = 60

And Q = Y

Hence, Y = 60.

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