Q. 24.7( 3 Votes )

For ΔPQR and ΔXYZ, the correspondence PQR YZX is a similarity. mP = 2mQ and mX = 120. Find mY.

Answer :

Given, ΔPQR and ΔXYZ

P = 2Q and X = 120


If the correspondence PQRYZX is a similarity then


mP = mX ... (i)


mQ = mY ... (ii)


mR = mZ ... (iii)


From eq. (i) and (ii)


P = 120


Because mP = 2mQ


Hence, 2Q = 120


Q = 60


And Q = Y


Hence, Y = 60.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Basic Proportionality Theorem42 mins
Quiz | Criterion of Similarity of Triangle45 mins
Champ Quiz | Thales Theorem49 mins
NCERT | Strong Your Basics of Triangles39 mins
RD Sharma | Imp. Qs From Triangles41 mins
R.D Sharma | Solve Exercise -4.2 and 4.3FREE Class
How to Ace Maths in NTSE 2020?36 mins
R.D Sharma | Solve Exercise-4.545 mins
NCERT | Basic Proportionality Theorem22 mins
RD Sharma | Imp Qs Discussion- Triangles43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses