Q. 17

# Prove that-2(cos245° + tan260°) – 6(sin245° – tan230°) = 6

tan60° = √3

tan260° = 3

LHS =

= 7 - 1

= 6

= RHS

LHS = RHS

(cos245° + tan260°) – 6(sin245° – tan230°) = 6

Hence Proved

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