Q. 115.0( 1 Vote )

# In a Δ</spa

Given: A MNO with MP as external bisector of M meeting NO produced at P, and MN = 10 cm, MO = 6 cm, NO = 12 cm

Required: Length of OP

In ΔMNP , MP is the external bisector of M meeting NO ant produced at P.

Let OP = x cm , Now by angle bisector theorem, we have

(x + 12)×6 = 10x

6x + 72 = 10x

10x—6x = 72

4x = 72

x = = 18

The value of x = 18 cm.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Section Formula53 mins
Doubt Session47 mins
Basics of Coordinate Geometry53 mins
Distance Formula52 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

E and F are pointTamil Nadu Board - Math

In the figure TP Tamil Nadu Board - Math

In a ΔABC, D and Tamil Nadu Board - Math

In the figuTamil Nadu Board - Math

E and F are pointTamil Nadu Board - Math

In the figuTamil Nadu Board - Math

ABCD is a qTamil Nadu Board - Math