Answer :
Expanding along the first row
= x2(2×4 – 1×1) – x(0×4 – 1×3) + 1(0×1 – 2×3)
= x2(8 – 1) – x(0 – 3) + 1(0 – 6)
= 7x2 + 3x –6
Also |A| = 28
⇒ 7x2 + 3x – 6 =28
⇒ 7x2 + 3x – 34 = 0
⇒ 7x2 + 17x – 14x – 34 = 0
⇒ x(7x+ 17) – 2(7x +17) = 0
⇒ (x–2)(7x +17) = 0
Integer value of x is 2.
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