Q. 83.7( 6 Votes )

In Fig. 6.8, PB = PD. The value of x is


A. 85°

B. 90°

C. 25°

D. 35°

Answer :

Exterior angle of triangle is equal to sum of 2 opposite onterior angles.


As BC is straight line


PBD + 120° = 180°


PBD = 180° - 120°


PBD = 60°


As ΔPBD is isosceles triangle and PB = PD


PBD = PDB


PDB = 60°


In ΔPSR


With exterior angle PSQ equal to sum of opposite inetrior angles


PDB = DPC + PCD


60° = x + 35°


x = 60° - 35°


x = 25°

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