# Maximum slope of

Given equation of curve is y = –x3 + 3x2 + 9x – 27

Now applying first derivative, we get Now applying the sum rule of differentiation and the differentiation of the constant term is 0 we get Now applying the power rule of differentiation we get  This is the slope of the given curve.

Now we will differentiate equation (i) once again to find out the second derivative of the given curve, Now applying the sum rule of differentiation and the differentiation of the constant term is 0 we get Now applying the power rule of differentiation we get  Now we will find the critical point by equating the second derivative to 0, we get

-6(x-1) =0

x-1=0

x=1

Now we will differentiate equation (ii) once again to find out the third derivative of the given curve, Now applying the sum rule of differentiation and the differentiation of the constant term is 0 we get Now applying the power rule of differentiation we get So the maximum slope of the given curve is at x=1

Now we will substitute x=1 in equation (i), we get  Hence the maximum slope of the curve y = –x3 + 3x2 + 9x – 27 is 12.

So the correct option is option B.

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