Q. 435.0( 1 Vote )

# In Fig. 6.18, M is the mid-point of both AC and BD. Then

A. ∠1 = ∠2

B. ∠1 = ∠4

C. ∠2 = ∠4

D. ∠1 = ∠3

Answer :

In Δ ABM and Δ DCM

AM = MC ∵ M is midpoint of AC

DM = BM ∵ M is midpoint of BD

∠AMB = ∠DMC ∵ Vertically opposite angles

AMB ↔ CMD

Hence, Δ ABM ≅ Δ DCM

By congruency criteria AMB ↔ CMD

∠1 = ∠4;and ∠2 = ∠3

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