Q. 415.0( 3 Votes )

In ∆ABC, A = 50°, B = 70° and bisector of C meets AB in D (Fig. 6.17). Measure of ADC is.


A. 50°

B. 100°

C. 30°

D. 70°

Answer :

Given: A = 50°, B = 70° and bisector of C meets AB in D


Formula Used/Theory:-


Angle Sum property


Sum of angles of triangle is 180°


In Δ ABC


A + B + C = 180°


50° + 70° + C = 180°


C = 180° - 120° = 60°


If CD is bisector of C


Then;


DCA = DCB = = 30°


In Δ ADC


A + DCA + ADC = 180°


50° + 30° + ADC = 180°


ADC = 180° - 80° = 100°

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