Q. 394.1( 7 Votes )

# What is the length of outer boundary of the park shown in Fig. 6.16? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs 50 per square metre.

Answer :

Perimeter = Sum of all sides

Perimeter = 200 + 300 + 80 + 300 + 200 + 260

= 1340 m

Rate of fencing = Rs 20

Total Rate = 20 × 1340

= Rs 26,800

Area of rectangular flower bed = 100 × 80

= 8000 m^{2}

Rate of manuring = Rs 50

So total rate = 50 × 8000

= Rs 4, 00,000

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