Q. 374.4( 7 Votes )

In an exhibition

Answer :

Given:


Total display boards = 24


Length of strip = 100 m


Length of one display board = 1 + 0.5


= 1.5 m


Breadth of one display board = 1 m


Perimeter of one display board = 2 × (l + b)


= 2 × (1.5 + 1)


= 5 m


Number of boards which will be framed = 100 / 5


= 20


Number of boards unframed = 24 – 20


= 4


Length of strip for required for remaining boards = 4 × Perimeter of one board


= 4 × 5


= 20 m.


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