Q. 245.0( 2 Votes )

In Fig. 6.13, BAC = 90°, AD BC and BAD = 50°, then ACD is


A. 50°

B. 40°

C. 70°

D. 60°

Answer :

Given: BAC = 90°, AD BC and BAD = 50°


Formula Used/Theory:-


Sum of all angles of triangle is 180°


As BAC = BAD + CAD


90° = 50° + CAD


CAD = 90° - 50° = 40°


In Δ ADC


ADC = 90° AD is perpendicular to BC


ADC + CAD + ACD = 180°


90° + 40° + ACD = 180°


130° + ACD = 180°


ACD = 180° - 130° = 50°

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