Q. 245.0( 2 Votes )
In Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is

A. 50°
B. 40°
C. 70°
D. 60°
Answer :
Given: ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°
Formula Used/Theory:-
Sum of all angles of triangle is 180°
As ∠BAC = ∠BAD + ∠CAD
90° = 50° + ∠CAD
∠CAD = 90° - 50° = 40°
In Δ ADC
∠ADC = 90° ∵ AD is perpendicular to BC
∠ADC + ∠CAD + ∠ACD = 180°
90° + 40° + ∠ACD = 180°
130° + ∠ACD = 180°
∠ACD = 180° - 130° = 50°
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