Q. 24.5( 2 Votes )

In ΔABC, <span la

Answer :

Given: A + B = 108°


A = 108° B


B + C = 130°


C = 130° B


We know sum of angles in a triangle is 180°.


A + B + C = 180°


(108° B) + B + (130° B) = 180°


-B + 238° = 180°


-B = -58°


B = 58°


Now, A = 108° B


A = 108° 58° = 50°


Also, C = 130° B


C = 130° 58° = 72°


Thus, A = 50°, B = 58° and C = 72°.


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