Q. 24.5( 2 Votes )

In ΔABC, <span la

Answer :

Given: ∠A + ∠B = 108°

⇒ ∠A = 108° – ∠B

∠B + ∠C = 130°

⇒ ∠C = 130° – ∠B

We know sum of angles in a triangle is 180°.

⇒ ∠A + ∠B + ∠C = 180°

⇒ (108° – ∠B) + ∠B + (130° – ∠B) = 180°

⇒ -∠B + 238° = 180°

⇒ -∠B = -58°

∴ ∠B = 58°

Now, ∠A = 108° – ∠B

⇒ ∠A = 108° – 58° = 50°

Also, ∠C = 130° – ∠B

⇒ ∠C = 130° – 58° = 72°

Thus, ∠A = 50°, ∠B = 58° and ∠C = 72°.

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