Q. 194.5( 4 Votes )

In Fig. 6.9, BC = CA and A = 40. Then, ACD is equal to


A. 40°

B. 80°

C. 120°

D. 60°

Answer :

Exterior angle is equal to sum of opposite interior angles


ACD = A + B


As ΔACB is isosceles triangle with AC = BC


Then A must be equal to B


ACD = 40° + 40° = 80°

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