Q. 1575.0( 4 Votes )

The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground, (a) Find the length of the ladder. (b) If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?

Answer :

Given: Height of window = 8m


Distance of ladder to wall = 6m


Formula Used/Theory:-


Pythagoras theorem:-


Base2 + Height2 = Hypotenuse2


Height of ladder (Hypotenuse)


Height of wall (Height) = 8m


Distance of wall and foot of ladder = 6m


Base2 + Height2 = Hypotenuse2


62 + 82 = Hypotenuse2


Hypotenuse2 = 36 + 64 = 100


Hypotenuse = √100 = 10m


(i) Height of ladder is 10m


(ii) If ladder is shifted 8m from wall


Then;


Base = 8m


Height of ladder will remain constant(Hypotenuse) = 10m


Distance of wall till ladder reach(Height)


Base2 + Height2 = Hypotenuse2


82 + Height2 = 102


Height2 + 64 = 100


Height2 = 100-64 = 36


Height = √36 = 6m


Ladder reach 6m above the ground


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