Q. 1575.0( 4 Votes )
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground, (a) Find the length of the ladder. (b) If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
Answer :
Given: Height of window = 8m
Distance of ladder to wall = 6m
Formula Used/Theory:-
Pythagoras theorem:-
Base2 + Height2 = Hypotenuse2
Height of ladder (Hypotenuse)
Height of wall (Height) = 8m
Distance of wall and foot of ladder = 6m
Base2 + Height2 = Hypotenuse2
62 + 82 = Hypotenuse2
Hypotenuse2 = 36 + 64 = 100
Hypotenuse = √100 = 10m
(i) Height of ladder is 10m
(ii) If ladder is shifted 8m from wall
Then;
Base = 8m
Height of ladder will remain constant(Hypotenuse) = 10m
Distance of wall till ladder reach(Height)
Base2 + Height2 = Hypotenuse2
82 + Height2 = 102
Height2 + 64 = 100
Height2 = 100-64 = 36
Height = √36 = 6m
Ladder reach 6m above the ground
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