Q. 148

In Fig. 6.50, whi

(i) QR = SU

QP = TU

Q = U

Hence; both triangles are congruent by SAS criterion

Δ PQR Δ TUS

(ii) JK = MN

JL≠NO

J = N

Hence; both triangles are not congruent by SAS criterion

(iii) AB = BC

AE = CD

A = C

Hence; both triangles are congruent by SAS criterion

Δ EAB Δ DCB

(iv) TS = XZ

TU = YZ

T = Z

Hence; both triangles are congruent by SAS criterion

Δ STU Δ XZY

(v) OD = OH

OF = OC

FOD = COH

Hence; both triangles are congruent by SAS criterion

Δ FOD Δ COH

(vi) AB = DE

AC≠DF

A = D

Hence; both triangles are not congruent by SAS criterion

(vii) SP = QR

SQ = SQ

PSQ = RQS

Hence; both triangles are congruent by SAS criterion

Δ PSQ Δ RQS

(viii) LM = OM

MN = MN

LMN = OMN

Hence; both triangles are congruent by SAS criterion

Δ LMN Δ OMN

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