Q. 117

In Fig. 6.34, find the measures of PON and NPO.


Answer :

Formula Used/Theory:-


Angle sum property


Sum of all angles of triangle is 180°


Exterior angle is equal to sum of interior opposite angles


In Δ LOM


LOP = MLO + LMO


= 70° + 20° = 90°


In Δ PON


LOP = NPO + PNO


90° = NPO + 70°


NPO = 90° - 70° = 20°


NPO + PNO + PON = 180° (Angle sum property)


20° + 70° + PON = 180°


PON = 180° - 90°


PON = 90°


Result:- PON = 90°; NPO = 20°


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