Q. 15.0( 3 Votes )

In ΔABC, <span la

Answer :

Given: A – B = 33°


A = 33° + B


B – C = 18°


C = B – 18°


We know the sum of angles in a triangle is 180°.


A + B + C = 180°


(33° + B) + B + (B – 18°) = 180°


3B + 15° = 180°


3B = 165°



Now, A = 33° + B


A = 33° + 55° = 88°


Also, C = B – 18°


C = 55° 18° = 37°


Thus, A = 88°, B = 55° and C = 37°.


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