# Write z = (–1 + i) in polar form.

we have, z = (–1 + i)

Let -1 = rcosθ and √3 = rsinθ

By squaring and adding, we get

(-1)2 + (√3)2 = (rcosθ)2 + (rsinθ)2

1+3 = r2(cos2θ + sin2θ)

4 = r2

r = 2

Since, θ lies in second quadrant, we have

Thus, the required polar form is

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Write 2i in polar form.

RS Aggarwal - Mathematics