# Write z = (1 – i) in polar form.

we have, z = (1 – i)

Let 1 = rcosθ and -1 = rsinθ

By squaring and adding, we get

(1)2 + (-1)2 = (rcosθ)2 + (rsinθ)2

1+1 = r2(cos2θ + sin2θ)

2 = r2

r = √2

Since, θ lies in fourth quadrant, we have

Thus, the required polar form is

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Write 2i in polar form.

RS Aggarwal - Mathematics