# Write –9 in polar form.

we have, z = –9

Let -9 = rcosθ and 0 = rsinθ

By squaring and adding, we get

(-9)2 + (0)2 = (rcosθ)2 + (rsinθ)2

81 = r2(cos2θ + sin2θ)

81 = r2

r = 9

Thus, the required polar form is 9(cos π+i sin π)

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RS Aggarwal - Mathematics