# If 64y8 is exactly divisible by 3, then the least value of y isA. 0B. 1C. 2D. 3

We know that if sum of digits of a number is divisible by 3, then the number is divisible by 3.

Here,

6 + 4 + y + 8 = multiple of 3

18 + y = 0, 3, 6, 9, ….

Hence,

18 + y = 18

y = 0

the least value of y is 0.

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