Q. 125.0( 3 Votes )

# Fill in the numbers from 1 to 6 without repetition, so that each side of the triangle adds up to 12.

Answer :

Place the largest numbers, i.e., 4, 5 and 6, at the three corners of the triangle.

Now, 4 + 5 = 9, 4 + 6 = 10 and 5 + 6 = 11

Therefore, by placing 3 between 4 and 5, 2 between 4 and 6, and 1 between 5 and 6 we get the desired magic triangle.

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PREVIOUSComplete the magic square given below, so that the sum of the numbers in each row or in each column or along each diagonal is 15.NEXTFibonacci numbers Take 10 numbers as shown below:a, b, (a + b), (a + 2b), (2a + 3b), (3a + 5b), (5a + 8b), (8a + 13b), (13a + 21b), and (21a + 34 b). Sum of all these numbers =11(5a + 8b) = 1 1 x 7th number.Taking a = 8, b =13; write 10 Fibonacci numbers and verify that sum of all these numbers =11 x 7th number.

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