Answer :

Given: z = (2 – 5i)2

First we calculate (2 – 5i)2 and then we find the conjugate


(2 – 5i)2 = (2)2 + (5i)2 – 2(2)(5i)


= 4 + 25i2 – 20i


= 4 + 25(-1) – 20i [ i2 = -1]


= 4 – 25 – 20i


= -21 – 20i


Now, we have to find the conjugate of (-21 – 20i)


So, the conjugate of (- 21 – 20i) is (-21 + 20i)


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