Q. 21 F4.3( 6 Votes )

Find the real values of x and y for which:



Answer :

Consider,



Taking LCM




Putting i2 = -1





4x + 2xi – 3i – 3 + 9y – 7iy = 10i


(4x – 3 + 9y) + i(2x – 3 – 7y) = 10i


Comparing the real parts, we get


4x – 3 + 9y = 0


4x + 9y = 3 …(i)


Comparing the imaginary parts, we get


2x – 3 – 7y = 10


2x – 7y = 10 + 3


2x – 7y = 13 …(ii)


Multiply the eq. (ii) by 2, we get


4x – 14y = 26 …(iii)


Subtracting eq. (i) from (iii), we get


4x – 14y – (4x + 9y) = 26 – 3


4x – 14y – 4x – 9y = 23


-23y = 23


y = -1


Putting the value of y = -1 in eq. (i), we get


4x + 9(-1) = 3


4x – 9 = 3


4x = 12


x = 3


Hence, the value of x = 3 and y = -1


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