Q. 21 F4.3( 6 Votes )

# Find the real values of x and y for which:

Consider,

Taking LCM

Putting i2 = -1

4x + 2xi – 3i – 3 + 9y – 7iy = 10i

(4x – 3 + 9y) + i(2x – 3 – 7y) = 10i

Comparing the real parts, we get

4x – 3 + 9y = 0

4x + 9y = 3 …(i)

Comparing the imaginary parts, we get

2x – 3 – 7y = 10

2x – 7y = 10 + 3

2x – 7y = 13 …(ii)

Multiply the eq. (ii) by 2, we get

4x – 14y = 26 …(iii)

Subtracting eq. (i) from (iii), we get

4x – 14y – (4x + 9y) = 26 – 3

4x – 14y – 4x – 9y = 23

-23y = 23

y = -1

Putting the value of y = -1 in eq. (i), we get

4x + 9(-1) = 3

4x – 9 = 3

4x = 12

x = 3

Hence, the value of x = 3 and y = -1

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