Answer :

Given: x + 4yi = ix + y + 3

or x + 4yi = ix + (y + 3)


Comparing the real parts, we get


x = y + 3


or x – y = 3 …(i)


Comparing the imaginary parts, we get


4y = x …(ii)


Putting the value of x = 4y in eq. (i), we get


4y – y = 3


3y = 3


y = 1


Putting the value of y = 1 in eq. (ii), we get


x = 4(1) = 4


Hence, the value of x = 4 and y = 1


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