Q. 13

If A = diag [2, -5, 9], B = diag [-3, 7, 14] and C = diag [4, -6, 3], find:

(i) A + 2B

(ii)B + C – A

Answer :


If Z = diag[a,b,c], then we can write it as



So, A+2B




=diag[4,9,37]


Conclusion: A + 2B = diag[4,9,37]


(Given answer is wrong)


ii. B + C – A


If Z = diag[a,b,c], then we can write it as



B+C-A



= diag[-1,6,8]


Conclusion: B+C-A = diag[-1,6,8]


iii. 2A + B – 5C


If Z = diag[a,b,c], then we can write it as



2A+B-5C




= diag[-19,27,17]


Conclusion: 2A + B – 5C = diag[-19,27,17]


(Given answer is wrong)


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