Q. 13

If A = diag [2, -5, 9], B = diag [-3, 7, 14] and C = diag [4, -6, 3], find:

(i) A + 2B

(ii)B + C – A

Answer :

If Z = diag[a,b,c], then we can write it as

So, A+2B


Conclusion: A + 2B = diag[4,9,37]

(Given answer is wrong)

ii. B + C – A

If Z = diag[a,b,c], then we can write it as


= diag[-1,6,8]

Conclusion: B+C-A = diag[-1,6,8]

iii. 2A + B – 5C

If Z = diag[a,b,c], then we can write it as


= diag[-19,27,17]

Conclusion: 2A + B – 5C = diag[-19,27,17]

(Given answer is wrong)

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