Answer :

Consider,


Now, rationalizing




In denominator, we use the identity


(a – b)(a + b) = a2 – b2






= (i)93 – (-i)3


= (i)92+1 – [-(i)3]


= [(i)92(i)] – [-(i2 × i)]


= [(i4)23(i)] – [- (-i)]


= [(1)23(i)] – i


= i - i


x + iy = 0


x = 0 and y = 0


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