# In a two-digit number, the digit at the unit place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.

Our first given condition is that the digit at the unit place is double the digit in the tens place.

Let the tens digit be y.
The digit in the units place is 2y.
Number = 10y + 2y = 12y

Now the second condition is that the number exceeds the sum of its digits by 18.

By given condition,

(y + 2y) + 18 = (10y + 2y)
3y + 18 = 12y
12y - 3y = 18
9y =18

y = 2

Hence, the digit in the tens place is 2.

So, digit in the units place is 4.

Our number is 24.

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