Q. 24.2( 47 Votes )

# In a two-digit number, the digit at the unit place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.

Answer :

Our first given condition is that the digit at the unit place is double the digit in the tens place.

∴ Let the tens digit be y.

The digit in the units place is 2y.

Number = 10y + 2y = 12y

Now the second condition is that the number exceeds the sum of its digits by 18.

∴ By given condition,

(y + 2y) + 18 = (10y + 2y)

∴ 3y + 18 = 12y

12y - 3y = 18

9y =18

∴ y = 2

Hence, the digit in the tens place is 2.

So, digit in the units place is 4.

∴ Our number is 24.

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