# In a two-digit number, the digit at the unit place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.

Our first given condition is that the digit at the unit place is double the digit in the tens place.

Let the tens digit be y.
The digit in the units place is 2y.
Number = 10y + 2y = 12y

Now the second condition is that the number exceeds the sum of its digits by 18.

By given condition,

(y + 2y) + 18 = (10y + 2y)
3y + 18 = 12y
12y - 3y = 18
9y =18

y = 2

Hence, the digit in the tens place is 2.

So, digit in the units place is 4.

Our number is 24.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Quiz on Divisibility Test32 mins  Divisible or not41 mins  Quiz | Imp. Qs. on Playing With Numbers45 mins  Quiz | Properties of Rational Numbers41 mins  Together With | Understanding Secularism53 mins  On the Number line44 mins  Essentials of Rational Numbers45 mins  Missing Numbers55 mins  Together With | Ruling the countryside52 mins  Properties of Rational Numbers29 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 