# In the given figure, AB=AC and OB=OC. Prove that ∠ABO=∠ACO. Give that AB=AC and OB=OC.

∆ABC and ∆OBC are isosceles triangle.

ABC = ACB and OBC = OCB ….(1)

Also,

ABC = ABO + OBC

And ACB = ACO + OCB

From 1 and above equations, we state that,

ABC = ABO + OBC

And ABC = ACO + OBC

This implies that,

ABO = ABC - OBC

And ACO = ABC - OBC

Hence,

ABO = ACO = ABC - OBC

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