Q. 134.2( 52 Votes )

# If y = 3 cos (log x) + 4 sin (log x), show that x^{2} y_{2} + xy_{1} + y = 0

Answer :

It is given that y = 3 cos (log x) + 4 sin (log x)

Now, on differentiating we get,

Again differentiating we get,

Therefore,

x^{2} y_{2} + xy_{1} + y

= -sin(logx) – 7cos(logx) + 4cos(logx) – 3sin(logx) + 3cos(logx) + 4sin(logx)

= 0

So, x^{2} y_{2} + xy_{1} + y = 0

Hence Proved

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