Q. 134.2( 52 Votes )

If y = 3 cos (log x) + 4 sin (log x), show that x2 y2 + xy1 + y = 0

Answer :

It is given that y = 3 cos (log x) + 4 sin (log x)


Now, on differentiating we get,






Again differentiating we get,







Therefore,


x2 y2 + xy1 + y



= -sin(logx) – 7cos(logx) + 4cos(logx) – 3sin(logx) + 3cos(logx) + 4sin(logx)


= 0


So, x2 y2 + xy1 + y = 0


Hence Proved


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