When the straight lines 3x + 6y + 7 = 0 and 2x + ky = 5 are perpendicular the product of their slopes should be equal to –1 .
Slope of 3x + 6y + 7 = 0 is:
Slope of 2x + ky = 5 is:
Now we have .
∴ when we substitute the values of m1 and m2 we get:
⇒ 1 = (–1)×k
⇒ 1 = –k or k = –1
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