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When the straight lines 3x + 6y + 7 = 0 and 2x + ky = 5 are perpendicular the product of their slopes should be equal to –1 .

Slope of 3x + 6y + 7 = 0 is: ; ( )

Slope of 2x + ky = 5 is: Now we have .

when we substitute the values of m1 and m2 we get:  1 = (–1)×k

1 = –k or k = –1

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