Answer :

We have, sinA = (9k)/(41k) = BC/AB (For some value of k)



By Pythagoras theorem, (hypotenuse)2 = (perpendicular)2 + (base)2


AB2 = BC2 + AC2


= (41k)2 = (9k)2 + AC2


= 1681k2 = 81k2 + AC2


AC2 = 1600k2


= (40k)2


AC = 40k


cosA = AC/AB = (40k)/(41k) = 40/41


tanA = BC/AC = sinA/cosA = 9/40


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