Answer :
We have, sinA = (9k)/(41k) = BC/AB (For some value of k)
By Pythagoras theorem, (hypotenuse)2 = (perpendicular)2 + (base)2
∴AB2 = BC2 + AC2
= (41k)2 = (9k)2 + AC2
= 1681k2 = 81k2 + AC2
AC2 = 1600k2
= (40k)2
→ AC = 40k
∴ cosA = AC/AB = (40k)/(41k) = 40/41
tanA = BC/AC = sinA/cosA = 9/40
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