# If 15 cotA = 8, find the values of sinA and secA.

We have, 15 cotA = 8

cotA = (8k)/(15k) = 1/tanA = AC/BC (For some value of k)

By Pythagoras theorem, (hypotenuse)2 = (perpendicular)2 + (base)2

AB2 = BC2 + AC2

AB2 = (15k)2 + (8k)2

AB2 = 225k2 + 64k2

AB2 = 289k2

= (17k)2

AB = 17k

sinA = BC/AB = (15k)/(17k) = 15/17

secA = 1/cosA = AB/AC = (17k)/(8k) = 17/8

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