Answer :

We have the A.P as 100, 97, 94, 91 …


So, a = 100


d= 97 – 100 = – 3


Now recall that, nth term of an AP is Tn = a + (n – 1)d


Tn = 100 + (n – 1)(– 3)


= 100 – 3n + 3


Tn = 103 – 3n


Since we need negative term, Tn < 0


So, 103 – 3n < 0


103 < 3n


< n


34.333 < n


n>34


i.e. N = 35


n=35 for the first negative term in the given A.P.


T35 = a + (35 – 1)d


= 100 + 34 × – 3


= 100 – 102


= – 2


the first negative term of the given AP is – 2.


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