Consider ΔABC to be a right - angled triangle.∴ tanA = BC/ACtanB = AC/BCGiven that tanA = tanBBC/AC = AC/BCBC2 = AC2→ BC = AC→ ∠ A = ∠ B (In a triangle, angles opposite to equal angles are equal)

Q. 314.2( 10 Votes )

If <span lang="EN

Class 10th RS Aggarwal - Mathematics 5. Trigonometric Ratios

Answer :

Consider ΔABC to be a right - angled triangle.

∴ tanA = BC/AC

tanB = AC/BC

Given that tanA = tanB

BC/AC = AC/BC

BC² = AC²

→ BC = AC

→ ∠ A = ∠ B (In a triangle, angles opposite to equal angles are equal)

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