Answer :

Given: The straight lines are 3x – 5y + 7 = 0 and


15x + 9y + 4 = 0 .


To Prove: The straight lines are 3x – 5y + 7 = 0 and


15x + 9y + 4 = 0 are perpendicular.


Proof: If two lines are perpendicular, then the product of their slopes is equal to –1.


The slope of the first line,3x –5y + 7 = 0 is


()


The slope of the second line, 15x + 9y + 4 = 0


is ()



Now the product of these slopes is m1×m2.



As the product of the slopes is –1, the lines are perpendicular to


each other.


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