Given: The straight lines are 3x – 5y + 7 = 0 and
15x + 9y + 4 = 0 .
To Prove: The straight lines are 3x – 5y + 7 = 0 and
15x + 9y + 4 = 0 are perpendicular.
Proof: If two lines are perpendicular, then the product of their slopes is equal to –1.
The slope of the first line,3x –5y + 7 = 0 is
The slope of the second line, 15x + 9y + 4 = 0
Now the product of these slopes is m1×m2.
As the product of the slopes is –1, the lines are perpendicular to
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