Q. 295.0( 1 Vote )

In the given figure, 0 is a point inside a ∠PQR such that ∠POR = 90°, OP = 6 cm and OR= 8 cm. If PQ = 24 cm and QR = 26 cm, prove that ΔPQR is right angled. P

Given: POR = 90°, OP = 6 cm and OR= 8 cm

and PQ = 24 cm and QR = 26 cm

To Prove: PQR is right angled at P

In ∆POR, using Pythagoras theorem, we get

(Perpendicular)2 + (Base)2 = (Hypotenuse)2

(PO)2 + (OR)2 = (PR)2

(6)2 + (8)2 = (PR)2

36 +64 = (PR)2

(PR)2= 100

PR =√100

PR = 10 [taking positive square root]

In ∆PQR

Using Pythagoras theorem, i.e. if the square of the hypotenuse is equal to the sum of the other two sides. Then, the given triangle is a right angled triangle, otherwise not.

Here, (PR)2 + (PQ)2

(10)2 + (24)2

= 100 + 576

= 676

= (26)2 = (QR)2

given sides 10cm, 24cm and 26cm make a right triangle right angled at P.

Hence Proved

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