If cosθ = 7/25, f

We have, cosθ = (7k)/(25k) = base/hypotenuse (For some value of k)

By Pythagoras theorem, (hypotenuse)² = (perpendicular)² + (base)²

∴AB² = BC² + AC²

= (25k)² = BC² + (7k)² (for some value of k)

= 625k² = BC² + 49k²

= BC² = 576k²

= BC² = (24k)²

→ BC = 24k

Hence, the trigonometric ratios of the given θ are:

sinθ = BC/AB = (24k)/(25k) = 24/25

cosθ = 7/25

tanθ = BC/AC = sinθ /cosθ = 24/7

cotθ = AC/BC = 1/tanθ = 7/24

cosecθ = AB/BC = 1/sinθ = 25/24

secθ = AB/AC = 1/cosθ = 25/7