Q. 15 J5.0( 1 Vote )

# If T4

Given T4 = 7

And we know that, Tn = a + (n – 1)d

So we have T4 = a + (4 – 1)d

7 = a + 3d …… (1)

Then, T7 = 4

T7 = a + (7 – 1)d

4 = a + 6d …….(2)

Now, (2) – (1) gives :

– 3 = 3d

d = – 1

so, now, putting value of d in (1),

7 = a + 3d

7 = a + 3( – 1)

7 = a – 3

a = 10

so now T10 = a + (10 – 1)d

T10 = a + 9d

= 10 + 9( – 1)

= 10 – 9

= 1

T10 = 1

correct option is (d)

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