Q. 153.7( 3 Votes )

# Find the length of altitude AD of an isosceles Δ ABC in which AB = AC = 2a units and BC = a units.

Given: ABC is an isosceles triangle

AB = AC = 2a and BC = a

and AD is the altitude on BC. Therefore, BC = 2BD

Now, In ∆ADB, using Pythagoras theorem, we have

(Perpendicular)2 + (Base)2 = (Hypotenuse)2

(AD)2 + (BD)2 = (AB)2

[taking positive square root]

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