# Two isosceles triangles have equal vertical angles and their areas are in the ratio 16 : 25. find the ratio of their corresponding heights. Let ABC and DEF are two isosceles triangles with AB =AC and DE = DF and A = D

Now, let AM and DN are their respective altitudes or heights.

Let ABC and DEF A = D [given] ABC ~ DEF [by SAS similarity]

We know that, in similar triangles, corresponding angles are in the same ratio.

⇒∠B = E and C = F ……(i)

In ABM and DEN

B = E [from (i)]

and M = N [each 90°] ABC ~ DEF [by AA similarity]

So, ……(ii)

We know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.  [from (ii)]  Rate this question :

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