# Find the equation

Let the x intercept be ‘a’. It is given that x intercept exceeds the y intercept by 5

y intercept = a– 5

The equation of the line using the intercept form is Substituting Value of b  x (a–5) + ya = a(a–5)

Given that the point (22, –6) lies on this equation of the line, hence it should satisfy it

22(a–5) + (–6) a = a(a–5)

22a – 110 – 6a = a2 –5a

a2 – 21a + 110 = 0

a(a–10) – 11(a –10) = 0

(a–11) (a–10)

a = 11 or 10

The equation of the line is

x(11–5) + 11y = 11(11–5)

6x + 11y – 66 = 0

Or

x(10–5) + 10y = 10(10–5)

5x + 10y– 50 = 0

x + 2y –10 = 0

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