# ΔABC is right angled at A and AD ⊥ BC. If BC = 13 cm and AC = 5 cm, find the ratio of the areas of ΔABC and ΔADC. and BC = 13 cm and AC = 5 cm

Let ABC and ADC

A = D [each 90°]

C = C [common angle] ABC ~ ADC [by AA similarity]

We know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.   Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Basic Proportionality Theorem42 mins  A Peep into Pythagoras Theorem43 mins  R.D Sharma | Solve Exercise -4.2 and 4.3FREE Class  NCERT | Strong Your Basics of Triangles39 mins  RD Sharma | Imp. Qs From Triangles41 mins  Champ Quiz | Thales Theorem49 mins  NCERT | Concept Based Questions on Triangles31 mins  Quiz | Criterion of Similarity of Triangle45 mins  How to Ace Maths in NTSE 2020?36 mins  Know About Important Proofs in Triangles33 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 