Answer :

Given


x cot (90° + θ) + tan (90° + θ) sin θ + cosec (90° + θ) = 0


x [-tan θ] + [-cot θ] sin θ + sec θ = 0





-x sin θ – cos2 θ + 1 = 0


We know that 1 – cos2 θ = sin2 θ


-x sin θ + sin2 θ = 0


x sin θ = sin2 θ


x = sin2 θ/ sin θ


x = sin θ


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