# Find the sum of t

Common difference = 18 – 14 = 4
a = a2 – d = 14 – 4 = 10
First term a = 10 and common difference d = 4

Since the sum of n terms is
Sn = Where,

a = First term of AP
d = Common difference of AP
and no of terms is ‘n’

So sum of first 51 terms S51 = 25.5 × [ 20 + 50×4]
= 25.5 × [ 20 + 200]
= 25.5 × 220
= 5610

Hence, Sum of first 51 terms is 5610.

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