Q. 40 D5.0( 1 Vote )

Solve the matrix

Answer :


Now we will multiply the two first matrices on LHS using the formula cij = ai1b1j + ai2b2j + … + ainbnj, we get




Again multiply these two LHS matrices, we get



x2 – 9x + 32x = 0


x2 – 23x. This is form of quadratic equation, we will solve this, we get


x(x – 23) = 0


x = 0 or x – 23 = 0


This gives, x = 0 or x = 23 is the required solution of the matrices.


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