Q. 40 C5.0( 3 Votes )

Solve the matrix

Answer :


Now we will multiply the two first matrices on LHS using the formula cij = ai1b1j + ai2b2j + … + ainbnj, we get




Again multiply these two LHS matrices, we get



x2 – 2x – 40 + 2x – 8 = 0


x2 – 48 = 0. This is form of quadratic equation, we will solve this, we get


x2 = 48 x2 = 16×3


This gives, x = ±4√3 is the required solution of the matrices.


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