Q. 40 B4.3( 3 Votes )

Solve the matrix

Answer :


Now we will multiply the two first matrices on LHS using the formula cij = ai1b1j + ai2b2j + … + ainbnj, we get




Again multiply these two LHS matrices, we get



4 + 4x = 0 we will solve this linear equation, we get


4x = – 4


This gives, x = – 1 is the required solution of the matrices.


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